The perimeter of a triangle whose sides are ЁЭСе+ЁЭСж+2z 2ЁЭСе+ЁЭСж+ЁЭСз ЁЭСОЁЭСЫЁЭСС ЁЭСе+2ЁЭСж+ЁЭСз is
The perimeter of a triangle whose sides are ЁЭСе+ЁЭСж+2z 2ЁЭСе+ЁЭСж+ЁЭСз ЁЭСОЁЭСЫЁЭСС ЁЭСе+2ЁЭСж+ЁЭСз is
Ans :- perimeter of a triangle = Add of all sides
= (x+y+2z) + (2x+y+z) + (x+2y+z)
= x+y+2z+2x+y+z+x+2y+z
= 4x+4y+4z
=4(x+y+z)
(Solved by -#Mkguhala)
Related searches
Types of triangle рдд्рд░िрднुрдЬ рдХे рдк्рд░рдХाрд░
рдЕрдкрд░िрдоेрдп рд╕ंрдЦ्рдпा рдХ्рдпा рд╣ोрддी рд╣ै
рдкрд░िрдоेрдп рд╕ंрдЦ्рдпा рдХ्рдпा рд╣ोрддी рд╣ै
Centre in triangle рдд्рд░िрднुрдЬों рдоें рдХेंрдж्рд░ рдпा рдХेрди्рдж्рд░рдХ
Polygon and triangle in english

Comments
Post a Comment